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Sagot :
The pH of a 1. 0 l buffer prepared by adding 0. 100 moles of NaOH to 0. 250 moles of HF. ka for HF = 3. 5 × 10−4 is 3.86.
What is Henderson hasselbalch equation?
The Henderson hasselbalch equation can be expressed as
pH = pKa + log [base]/ [acid]
Firstly we will calculate the value of pKa
pKa = -logKa
Given,
Ka = 3. 5 × 10−4)
pKa = -log(3. 5 × 10−4)
pKa = 3.46
Now, we will calculate the value of log [base]/ [acid]
Given,
[base] = 0.10m
[acid] = 0.25m
log [base]/ [acid] = log(0.10/0.25)
= 0.4
Putting the values in handerson hasselbalch equation,
pH = 3.46+0.4
= 3.86
Thus, we find that the value of pH of a 1. 0 l buffer prepared by adding 0. 100 moles of NaOH to 0. 250 moles of HF is 3.86.
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