Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
All subsets of the set s = {(i, 0), (0, i), (i, i)} that form a basis for r2 is
{( 0,1) (-1,1)}
{(1,0)(0,1)}
{(1,0)(-1,1)}
A fixed A is a subset of some other set B if all elements of set A are factors of set B. In other phrases, set A is contained within set B. The subset relationship is denoted as A⊂B.
Subsets are a part of one of the mathematical ideas known assets. a hard and fast is a set of items or factors, grouped within the curly braces, consisting of {a,b,c,d}. If a set A is a set of even numbers and set B includes {2, 4,6}, then B is stated to be a subset of A, denoted by B⊆A and A is the superset of B.
In mathematics, set A is a subset of a fixed B if all factors of A are also elements of B; B is then a superset of A. It's far possible for A and B to be equal; if they may be unequal, then A is a proper subset of B. The relationship of one set being a subset of every other is known as inclusion.
A set which is (is linearly independent andoil generates/ spans the space (like R) is called a baris.
S= (1,0), (0,1), (-1))}
option-1
As, dimension of R²=2, so, Ary set
conists of three vectors cannot be baris for R²
so, option-1 is wrong.
option-2
As, dimention of R2-2.
{(10), (-11)} is a linearly independent
subset of S. so And as, this subset
has 2 vectors so it will as also
span R se, it will be a baris
of IR?
So, option-6 is correct
{(0,1)} is linearly independent subset
option-7
As (LO) has one vector. So, it cannot
Span/generate R so, it also cannot be balis
for R2
of S.
But it cannot span R²
So ut cannot
be a baris of R2
se, option-2 is wrong.
Option-3
AS, {(0,1), (-1,1)} is linearly independent
So, option -7, is wrong.
Answer
[as fox amy KER, (-1,1) K (0,1)] subset of s
And also as dim {(0,1), (-11)}=2
which is same as the dimention of IR2
so {(0,1), (-11)} forms a baris of R2
{(1,0), (0,1), (-11)}
{(1,0)}
So, option-3 is
Connect
option-4
{(1,0), (3, 1)} is standard balis of R2
which is subset of S.
10
[{(1,0), (0,1)}]
So, option-4 is correct.
option-5
{(-11)}
consists of one vertex,
so, ut cannot span R², so, ut cannot
be a baris of R²
9090
LO {(1,0), (-1,1)}]
Learn more about subsets here https://brainly.com/question/2000547
#SPJ4
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.
