Answered

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Heat is added to 1. 81 kg of ice at -19 °c. how many kilocalories are required to change the ice to steam at 152 °c?

Sagot :

Answer:

1363.2 kilocalories

Explanation:

Heat up the ice ==> melt the ice to water ==> heat the water ==> vaporize the water to steam ==> heat the stem 52 degrees to 152

1.81 kg * (spec heat of ice * 19  +* heat of fusion of water + specific heat of water *100 +  heat of vaporization of water + specific heat of steam* 52)

1810 g  * ( .50 cal/g -C * 19 C    +  79.7 cal / g   +  1 cal/g-C  *100C   +  539 cal/g + .48 cal/g * 52 C ) = 1 363 219.6 calories

(check my math)

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