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Enter your answer in the provided box. calculate the ph of a 0. 011 m naf solution. (ka for hf = 7. 1 × 10−4. )

Sagot :

pH value of a 0. 011 m naf solution is 8.57.

Solution

This problem uses the relationship between Kb and the dissociation constants which is expressed as Kw = KaKb. Calculations are as follows:

Kb = KaKb

1.00 x 10^-14 = 7.2 x 10^-4(x)

x = 1.39 x 10^-11

We now need to calculate the [OH¯] using the Kb expression:

1.39 x 10^-11 = x^2 / (0.30 - x)

The denominator can be neglected. Thus, x is 3.73 x 10^-6.

pOH = -log 3.73 x 10^-6 = 5.43

pH = 14-5.43 = 8.57

To learn more ph of naf solution refer here:

https://brainly.com/question/1411794

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