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Sagot :
Six different sized rectangles that have an area of 64 square units:
1) 64 units x 1 unit
2) 32 units x 2 units
3) 16 units x 4 units
4) 40 units x 1.4 units
5) 20 units x 3.2 unit
6) 10 units x 6.4 units
For given question,
Let l be the length of the rectangle and w be the width of the rectangle.
We know that, the area of a rectangle is equal to
A = l × w
Here, A = 64 square units
So, we get an equation
l × w = 64 ...............................(1)
let's assume different values of l to get the different values of w.
Case 1) For l = 64 units
substitute in the equation 1
⇒ 64 × w = 64
⇒ w = 64/64
⇒ w = 1 units
The dimensions of the rectangle are 64 units x 1 unit
See the draw in the attached figure 1
Case 2) For l = 32 units
substitute in the equation 1
⇒ 32 × w = 64
⇒ w = 64/32
⇒ w = 2 units
The dimensions of the rectangle are 32 units x 2 unit
See the draw in the attached figure 2
Case 3) For l = 16 units
substitute in the equation 1
⇒ 16 × w = 64
⇒ w = 64/16
⇒ w = 4 units
The dimensions of the rectangle are 16 units x 4 unit
See the draw in the attached figure 3
Case 4) For l = 40 units
substitute in the equation 1
⇒ 40 × w = 64
⇒ w = 64/40
⇒ w = 1.4 units
The dimensions of the rectangle are 40 units x 1.4 unit
See the draw in the attached figure 4
Case 5) For l = 20 units
substitute in the equation 1
⇒ 20 × w = 64
⇒ w = 64/20
⇒ w = 3.2 units
The dimensions of the rectangle are 20 units x 3.2 unit
See the draw in the attached figure 5
Case 6) For l = 10 units
substitute in the equation 1
⇒ 10 × w = 64
⇒ w = 64/10
⇒ w = 6.4 units
The dimensions of the rectangle are 10 units x 6.4 unit
Learn more about the rectangle here:
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