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How many moles of HNO3 will be produced
from the reaction of 46.5 g of NO2 with excess
water in the following chemical reaction?
3 NO₂(g) + H₂O (1)→ 2 HNO3(g) + NO(g)

Sagot :

CrystalQueen

Answer:

0.674 moles HNO₃

Explanation:

To find the moles of HNO₃, you need to (1) convert grams NO₂ to moles NO₂ (via molar mass) and then (2) convert moles NO₂ to moles HNO₃ (via mole-to-mole ratio from equation coefficients). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (46.5 g).

Molar Mass (NO₂): 14.007 g/mol + 2(15.998 g/mol)

Molar Mass (NO₂): 46.003 g/mol

3 NO₂(g) + H₂O (l) ------> 2 HNO₃(g) + NO(g)

46.5 g NO₂            1 mole                2 moles HNO₃
-------------------  x  -------------------  x  --------------------------  =  0.674 moles HNO₃
                              46.003 g             3 moles NO₂

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