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Suppose the six people consist of three mar- ried couples and each couple wants to sit together with the older partner on the left. how many ways can the six be seated together in the row?

Sagot :

6 possible ways to order 3 couples in a row

Given,

We have three married couples. that is six persons in total.

a, b, c, d, e, f may taken as the six persons.

Considering the statement:

Elder partner on the left, assume a, c and e as elders.

Then we have, (a, b) ------ ( 1)

                        (c, d) ------ (2)

                        (e, f) ------ (3)

There is no change in position between the couples.

So, we get three persons in total.

Possible ways to order these three persons will be like this: 3! = 3×2×1

                                                                                                        = 6

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