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How many milliliters of a 9. 0 mh2so4 solution are needed to make 0. 45 l of a 3. 5 m solution?

Sagot :

There are 1157.14 milliliters of a 9. 0 M [tex]H_{2} SO_4}[/tex] solution are needed to make 0. 45 L of a 3. 5 M solution.

Calculation,

The formula for the dilution of a solution is given as:

[tex]M_{1} V_{1}[/tex] = [tex]M_{2} V_{2}[/tex]

Where M is molarity and V is the volume of the solution in liters ( L ).

Given data,

[tex]M_{1}[/tex] =  9. 0 M

[tex]V_{1}[/tex] = 0. 45 L

[tex]M_{2}[/tex] = 3. 5 M

[tex]V_{2}[/tex] = ?

9. 0 M ×0. 45 =  3. 5 M × [tex]V_{2}[/tex]

[tex]V_{2}[/tex] in Lit = 9. 0 M ×0. 45/ 3. 5 M = 1.15 L

[tex]V_{2}[/tex] in the ml = 1.15 × 1000ml = 1157.14 ml

Volume in milliliters is 1157.14 .

to learn more about dilution

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