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Sagot :
The estimated standard error for the sample is 6
Given,
Sample size, n = 36
Sample variance, [tex]s^{2}[/tex] = 1296
Standard deviation, s = √1296
= 36
Standard error, SE = [tex]\frac{s}{\sqrt{n} }[/tex]
= [tex]\frac{36}{\sqrt{36} }[/tex]
= [tex]\frac{36}{6}[/tex]
= 6
Concept
- Sample size is the number of participants or observations included in a study. It is denoted by ‘n’
- Sample variance is a measure of the degree to which the numbers in a list are spread out. It is denoted by '[tex]s^{2}[/tex]'
- Standard deviation is a measure of how dispersed the data is in relation to the mean. It is denoted by ‘s’
Learn more about standard deviation here:https://brainly.com/question/13905583
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