The rectangular equation for given parametric equations x = 2sin(t) and y = -3cos(t) on 0 ≤ t ≤ π is [tex]\frac{x^{2} }{4} +\frac{y^2}{9} =1[/tex] which is an ellipse.
For given question,
We have been given a pair of parametric equations x = 2sin(t) and y = -3cos(t) on 0 ≤ t ≤ π.
We need to convert given parametric equations to a rectangular equation and sketch the curve.
Given parametric equations can be written as,
x/2 = sin(t) and y/(-3) = cos(t) on 0 ≤ t ≤ π.
We know that the trigonometric identity,
sin²t + cos²t = 1
⇒ (x/2)² + (- y/3)² = 1
⇒ [tex]\frac{x^{2} }{4} +\frac{y^2}{9} =1[/tex]
This represents an ellipse with center (0, 0), major axis 18 units and minor axis 8 units.
The rectangular equation is [tex]\frac{x^{2} }{4} +\frac{y^2}{9} =1[/tex]
The graph of the rectangular equation [tex]\frac{x^{2} }{4} +\frac{y^2}{9} =1[/tex] is as shown below.
Therefore, the rectangular equation for given parametric equations x = 2sint and y = -3cost on 0 ≤ t ≤ π is [tex]\frac{x^{2} }{4} +\frac{y^2}{9} =1[/tex] which is an ellipse.
Learn more about the parametric equations here:
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