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Sagot :
The original molarity of an aqueous solution of ammonia whose pH is 11. 02 at 25°C is 0.556 M
Calculation ,
Given : pH = 11.5
[tex][H^{+} ][/tex] = [tex]10^{-11.5}[/tex]
[tex][OH^{-} ][/tex] = [tex]K_{w} /[H^{+} ][/tex] = [tex]10^{-14}[/tex]/ [tex]10^{-11.5}[/tex] = [tex]10^{-2.5}[/tex] M
Kb = [tex][NH_{4}^{+} ][OH^{-} ]/[NH_{4} OH][/tex] = [tex](10^{-2.5})^{2} /C[/tex] = 1.8×[tex]10^{-5}[/tex] M
C = 1/1.8 = 0.566 M
So, molarity of an aqueous solution of ammonia is 0.566 M
pH ia a measure of hydrogen ion concentration , a measure of acidity or alkalinity of the solution .pH scale usually range from 0 to 14 Aqueous solutions at 25°C witha pH less rhan 7 are acidic , whereas , those with pH greater than 7 are basic or alkaline. pOH ia a measure of hydroxide ion concentration , a measure of alkalinity of the solution .
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