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Sagot :
The products formed when ester is treated with lithium hydroxide and water is given below.
[tex]CH_{3} CH_{2} CH(CH_{3} )OC=OCH(CH_{3} )_{2} +LiOH +H_{2} O[/tex]→[tex]CH_{3} CH_{2} CH(CH_{3} )OH+LiOC=OCH(CH_{3} )_{2} +H_{2} O[/tex]
The products formed when ester is treated with lithium hydroxide and water is alcohol and salt of acid.
The reaction of ester with water in the presence of base is called hydrolysis of ester in the presence of base. The product of hydrolysis of of ester in the presence of base ( lithium hydroxide ) is alcohol and salt of acid.
The hydrolysis of ester is also takes place in the presence of acid and give the product of alcohol and carboxylic acid. Lithium hydroxide is an inorganic base and it is soluble in water and slightly soluble in ethanol. The Lithium hydroxide is less soluble in water as compare to sodium hydroxide due to the anomalous behavior shown by lithium from rest of the family member.
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