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If a linear piece of dna has three sites for a particular restriction enzyme, into how many fragments will that restriction enzyme cut the dna?

Sagot :

If a linear piece of DNA has three sites for a particular restriction enzyme, it will be cut into 4 fragments. If the DNA is circular, the number of obtained fragments will be N for N recognition sequences for the specified restriction enzymes however if the DNA is linear, the number of obtained fragments will be (N+1).

A bacterial protein called the restriction enzyme cleaves DNA at specific  locations. The recognition sequences, or short and distinct nucleotide sequences, are recognized by restriction enzymes in DNA. When a DNA sequence is recognized by the restriction enzyme, it hydrolyzes the bond between neighboring nucleotides and cleaves the DNA molecule.

The restriction enzymes guard against bacteriophages on the living bacteria. They identify the bacteriophage and cleave at its restriction sites, destroying its DNA.

The use of restriction enzymes in genetic engineering is crucial. In order to introduce foreign DNA for gene-editing purposes, restriction enzymes cut DNA at a specified location, which makes them a crucial tool.

To learn more about restriction enzyme, recognition sequences and bacteriophages here

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