Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
For function g(x, y) = 9x² + 6y²,
the absolute minimum is 15 and the absolute maximum is 303
For given question,
We have been given a function g(x, y) = 9x² + 6y² subject to the constraint −1≤x≤1 and −1≤y≤7
We need to find the absolute maximum and minimum values of the function.
First we find the partial derivative of function g(x, y) with respect to x.
⇒ [tex]g_x=18x[/tex]
Now, we find the partial derivative of function g(x, y) with respect to x.
⇒ [tex]g_y=12y[/tex]
To find the critical point:
consider [tex]g_x=0[/tex] and [tex]g_y=0[/tex]
⇒ 18x = 0 and 12y = 0
⇒ x = 0 and y = 0
This means, the critical point of function is (0, 0)
We have been given constraints −1 ≤ x ≤ 1 and −1 ≤ y ≤7
Consider g(-1, -1)
⇒ g(-1, -1) = 9(-1)² + 6(-1)²
⇒ g(-1, -1) = 9 + 6
⇒ g(-1, -1) = 15
And g(1, 7)
⇒ g(1, 7) = 9(1)² + 6(7)²
⇒ g(1, 7) = 9 + 294
⇒ g(1, 7) = 303
Therefore, for function g(x, y) = 9x² + 6y²,
the absolute minimum is 15 and the absolute maximum is 303
Learn more about the absolute maximum and absolute minimum values of the function here:
https://brainly.com/question/16270755
#SPJ4
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
