Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
The thermodynamic efficiency of a heat engine that rejects heat at a rate of 20 mw when heat is supplied to it at a rate of 60 mw is 66.67%.
It is given that,
Rejected heat at the rate of 20 mw and supplied heat a rate of 60 mw.
It is required to find the thermodynamic efficiency of a heat engine.
What is the thermodynamic efficiency of a heat engine that rejects heat at a rate of 20 mw when heat is supplied to it at a rate of 60 mw?
As we know that
Work Done = Heat Supplied - Heat Rejected
Work Done = 60 mw - 20 mw
Work Done = 40 mw
So the efficiency of heat engine will be:
[tex]\eta=\frac{Work done}{Heat energy supply}[/tex]
[tex]\eta=\frac{40}{60}[/tex]×[tex]100\\[/tex]
η = [tex]\frac{2}{3}[/tex]×[tex]100\\[/tex]
η = 66.67%
Thus, thermodynamic efficiency of a heat engine that rejects heat at a rate of 20 mw when heat is supplied to it at a rate of 60 mw is 66.67%.
Learn more about thermodynamic efficiency here:
https://brainly.com/question/887978
#SPJ4
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.
