Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
There are 372 grams of calcium phosphate are theoretically produced if we start with 3. 40 moles of calcium nitrate and 2. 40 moles of lithium phosphate .
Calculation,
The reactant or reagent that produces the least moles of the products is called limiting reagents. When limiting reagents used up , the reaction stops.
The balanced equation is given as,
[tex]3Ca(NO_{3} )_{2} + 2Li_{3} ( PO_{4} )[/tex] → [tex]3LiNO_{3} + Ca_{3}( PO_{4} )_{2}[/tex]
Multiply the moles of each reactant by the mole ratio between it and calcium phosphate in the balanced equation . so that the moles of the reactant cancel , leaving moles of calcium phosphate.
3.4 mol of calcium nitrate × 1 mol calcium phosphate / 3 mol calcium nitrate = 1.13 mol calcium phosphate
2.4 mol of lithium phosphate× 1 mol calcium phosphate / 2 mol lithium phosphate = 1.02 mol calcium phosphate
So, calcium nitrate is limiting reactant .
Calculation of mass of 1.02 mol calcium phosphate.
Multiply the moles of calcium phosphate by its molar mass.
molar mass of calcium phosphate = 3×40.078 g/mol calcium ion+2×30.9 g/mol phosphorus + 8×15.99 g/mol calcium phosphate = 310.178 g/mol calcium phosphate
1.20 mol calcium phosphate × 310.178 g/mol = 372 gram
learn more about calcium phosphate
https://brainly.com/question/11082654
#SPJ4
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.
