Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
There are 372 grams of calcium phosphate are theoretically produced if we start with 3. 40 moles of calcium nitrate and 2. 40 moles of lithium phosphate .
Calculation,
The reactant or reagent that produces the least moles of the products is called limiting reagents. When limiting reagents used up , the reaction stops.
The balanced equation is given as,
[tex]3Ca(NO_{3} )_{2} + 2Li_{3} ( PO_{4} )[/tex] → [tex]3LiNO_{3} + Ca_{3}( PO_{4} )_{2}[/tex]
Multiply the moles of each reactant by the mole ratio between it and calcium phosphate in the balanced equation . so that the moles of the reactant cancel , leaving moles of calcium phosphate.
3.4 mol of calcium nitrate × 1 mol calcium phosphate / 3 mol calcium nitrate = 1.13 mol calcium phosphate
2.4 mol of lithium phosphate× 1 mol calcium phosphate / 2 mol lithium phosphate = 1.02 mol calcium phosphate
So, calcium nitrate is limiting reactant .
Calculation of mass of 1.02 mol calcium phosphate.
Multiply the moles of calcium phosphate by its molar mass.
molar mass of calcium phosphate = 3×40.078 g/mol calcium ion+2×30.9 g/mol phosphorus + 8×15.99 g/mol calcium phosphate = 310.178 g/mol calcium phosphate
1.20 mol calcium phosphate × 310.178 g/mol = 372 gram
learn more about calcium phosphate
https://brainly.com/question/11082654
#SPJ4
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.
