Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Be sure to answer all parts. an aqueous solution of a strong base has a ph of 10. 220 at 25°c. calculate the concentration of the base if the base is (a) lioh: × 10 m (b) ba(oh)2: × 10 m

Sagot :

An aqueous solution of a strong base has a pH of 10. 220 at 25°C then concentration of the base if the base is

(a)  LiOH =  1.66×[tex]10^{-4}[/tex]  M

(b)  [tex]Ba(OH)_{2[/tex] =  3.32×[tex]10^{-4}[/tex]M

Calculation ,

For calculation of concentration of the   LiOH and  [tex]Ba(OH)_{2[/tex] first we have to calculate pOH of the solution.

pH + pOH = 14

pOH = 14 - pOH = 14 - 10.22  = 3.78

pOH = -㏒ [ [tex]OH^{-}[/tex] ]

[ [tex]OH^{-}[/tex] ] = [tex]10^{-pH}[/tex] =  [tex]10^{-3.78}[/tex] = 1.66×[tex]10^{-4}[/tex]

So ,  concentration of the base LiOH =  1.66×[tex]10^{-4}[/tex]

So ,  concentration of the base [tex]Ba(OH)_{2[/tex] =  1.66×[tex]10^{-4}[/tex] ×2 = 3.32×[tex]10^{-4}[/tex]

To learn more about strong base please click here

https://brainly.com/question/16749233

#SPJ4