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Sagot :
Then the new pressure of the sample of nitrogen is 1.28 atm
So, option D is correct one.
Calculation,
Formula used : [tex]P_{1} V_{1} /T_{1} =P_{2} V_{2}/T_{2}[/tex] (i)
Where , P is pressure and V is the volume
Given data,
[tex]P_{1}[/tex] = 3. 65 atm
[tex]V_{1}[/tex] = 21. 2 L
[tex]P_{2}[/tex] =
[tex]V_{2}[/tex] = 62. 6 L
[tex]T_{1}[/tex] = 22°C = 22+273 = 295 K
[tex]T_{2}[/tex] = 34°C = 34 +273 = 307 K
Putting the value of all data given in equation (i) we get,
3. 65 atm × 21. 2 L/295 K = [tex]P_{2}[/tex] × 62. 6 L / 307 K
[tex]P_{2}[/tex] = 3. 65 atm × 21. 2 L × 307 K/295 K × 62. 6 L = 1.28 atm
Then the new pressure the sample of nitrogen is 1.28 atm
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