At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
A 45. 0 L gas cylinder contains 988 g He at 23 °C then pressure inside the cylinder is 134.67 atm.
Calculation,
Formula used :The ideal gas equation is given as,
PV = nRT ....(i)
Where , P is pressure of the gas = ?
V = volume of the gas = 45. 0 L
R = universal gas constant = 0. 08206 L⋅atm/mol⋅K
T = Temperature = 23 °C = 23 + 273 = 299 K
n = number of moles = given mass/ molar mass = 988 g/4 = 247 moles
Putting the value of P , V , T , R and n in equation (i) we get
P×45. 0 L = 247 moles× 0. 08206 L⋅atm/mol⋅K×299 K
P = 247 moles× 0. 08206 L⋅atm/mol⋅K×299 K /45. 0 L = 134.67 atm
learn more about pressure
https://brainly.com/question/12611523
#SPJ4
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.