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A 45. 0 l gas cylinder contains 988 g he at 23 °c. what is the pressure inside the cylinder? (r = 0. 08206 l⋅atm/mol⋅k)
a. 10. 4 atm
b. 533 atm
c. 41. 4 atm
d. 133 atm
e. 101 atm

Sagot :

A 45. 0 L gas cylinder contains 988 g He at 23 °C then pressure inside the cylinder is  134.67 atm.

Calculation,

Formula used :The ideal gas equation is given as,

PV = nRT                       ....(i)

Where , P is pressure of the gas = ?

V = volume of the gas =  45. 0 L

R = universal gas constant =  0. 08206 L⋅atm/mol⋅K

T = Temperature = 23 °C = 23 + 273 = 299 K

n = number of moles = given mass/ molar mass =  988 g/4 = 247 moles

Putting the value of P , V , T , R and n in equation (i) we get

P×45. 0 L  =  247 moles× 0. 08206 L⋅atm/mol⋅K×299 K

P = 247 moles× 0. 08206 L⋅atm/mol⋅K×299 K /45. 0 L = 134.67 atm

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