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The perimeter of a rectangle is 320 feet. Find the length and width if the length is an odd integer and the width is 5 times the next consecutive odd integer.

The Perimeter Of A Rectangle Is 320 Feet Find The Length And Width If The Length Is An Odd Integer And The Width Is 5 Times The Next Consecutive Odd Integer class=

Sagot :

The length is 25 feet and the width is 135 feet

What are consecutive odd integers?

Consecutive odd integers differ by 2. If x is an odd integer, then x + 2, x + 4 and x + 6 are consecutive odd integers.

How to find the perimeter of the rectangle?

⇒Perimeter of rectangle = 2(l+w)

The perimeter of a rectangle is 320 feet

let the length of a rectangle is x

The next consecutive odd integer is x+2

width = 5(x+2)

=5x+10

2(length + width) = 320

l+w=160

x+5x+10=160

6x=150

x=25

length = 25 feet

width = 5(25+2)=135 feet

learn more about consecutive odd integers here :

https://brainly.com/question/263881

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