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How many milliliters of 10. 5 m hcl(aq) are needed to prepare 225. 0 ml of 1. 00 m hcl(aq)?

Sagot :

There are  21.42 milliliters of a 10. 5 M HCl(aq) are needed to prepare 225. 0 ml of 1. 00  M HCl(aq)

Calculation,

The formula for the dilution of a solution is given as:

[tex]M_{1} V_{1} =M_{2} V_{2}[/tex]

Where M is molarity and V is the volume of the solution in liters ( L ).

Given data,

[tex]M_{1}[/tex] =   10. 5 M

[tex]V_{1}[/tex] = ?

[tex]M_{2}[/tex] = 1. 00 M

[tex]V_{2}[/tex] = 225. 0 ml

10. 5 M × [tex]V_{1}[/tex] = 1. 00 M×225. 0 ml  

[tex]V_{1}[/tex]  in milliliters = 1. 00 M×225. 0 ml / 10. 5 M = 21.42 ml

Volume in milliliters is  21.42 ml .

to learn more about dilution

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