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How many milliliters of an aqueous solution of 0. 195 m sodium sulfate is needed to obtain 4. 27 grams of the salt?

Sagot :

onyebuchinnaji

The volume of the aqueous solution of sodium sulfate required is 153.85 mL.

Number of moles of the salt

The number of moles of the salt in the given mass is calculated as follows;

moles = reacting mass / molar mass

molar mass of  sodium sulfate = 142 g/mole

moles = (4.27) / (142)

moles = 0.03 mole

Volume of the aqueous solution of sodium sulfate

Concentration = moles/volume in liters

0.195 = 0.03/V

V = 0.03/0.195

V = 0.15385 liters

V = 153.85 mL

Thus, the volume of the aqueous solution of sodium sulfate required is 153.85 mL.

Learn more about volume here: https://brainly.com/question/1972490

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