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Sagot :
Lines BC and EF have the opposite and reciprocal slopes given that triangle ABC has been rotated 90° to create triangle DEF. This can be obtained by finding the slopes of each line and comparing them.
Prove that lines BC and EF have the opposite and reciprocal slopes:
- Slope of a line can be obtained using the equation,
m = rise/run = Δy/Δx = (y₂ - y₁)/(x₂ -x₁)
where m is the slope of the triangle, (x₁, y₁) and (x₂, y₂) are the endpoints of the lines. (y₂ - y₁) is the rise and (x₂ -x₁) is the run.
- Slope of a line can also be found using the formula,
m = rise/run = Δy/Δx = tan(∅)
where ∅ is the angle between Δx(run) and hypotenuse
From the question we can calculate the slope using the formula of slope,
- In triangle ABC,
(4, 5) and (1, 2) are the endpoints of the line BC
Slope of the line BC,
m₁ = (y₂ - y₁)/(x₂ -x₁) = (2 - 5)/(1 - 4)
m₁ = -3/-3
m₁ = 1
- In triangle DEF,
(2, -1) and (5, -4) are the endpoints of the line EF
Slope of the line EF,
m₂ = (y₂ - y₁)/(x₂ -x₁) = (-4 - (-1))/(5 - 2)
m₂ = -3/3
m₂ = - 1
Slope of the line BC is 1 and slope of line EF is - 1, and 1 and - 1 are opposite and reciprocal.
Since lines BC and EF have the opposite and reciprocal slopes given that triangle ABC has been rotated 90° to create triangle DEF.
Learn more about slopes here:
brainly.com/question/17870676
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