Answered

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If the current in an inductor is doubled, by what factor is the stored energy multiplied?
a. 4
b. 1/4
c. 2
d. 1/2
e. 1

Sagot :

Reideen

Answer:

  • a. 4

Explanation:

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[tex]I_2=2I_1[/tex]

[tex]L=\text{const}[/tex]

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[tex]\displaystyle \frac{W_2}{W_1}\; - \;?[/tex]

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[tex]\displaystyle \boldsymbol{\frac{W_2}{W_1}}=\frac{\dfrac{LI_2^2}{2} }{\dfrac{LI_1^2}{2} } =\frac{I_2^2}{I_1^2} =\bigg(\frac{I_2}{I_1} \bigg)^2=\bigg(\frac{2I_1}{I_1} \bigg)^2=2^2=\boldsymbol{4}[/tex]

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