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There are 3
denominations of bills in a wallet: $1, $5, and $10.
There are 5 fewer $5-bills than $1-bills. There are half as many
$10-bills as $5-bills. If there is $115 altogether, find the number of
each type of bill in the wallet.

Sagot :

The number of $1, $5 and $10 are 49, 44 and 22 respectively.

How to use equation to find the number of bills?

There are 3 denominations of bills in a wallet: $1, $5, and $10.

There are 5 fewer $5-bills than $1-bills.

let

x = number of $1 bills

Hence,

number of $5 bills = x - 5

There are half as many $10-bills as $5-bills.

number of $10 bills = 1 / 2 (x - 5)

Therefore,

x + x - 5 + 1 / 2 (x - 5) = 115

2x - 5  + 1 / 2 x - 5 / 2 = 115

2x + 1 / 2 x - 5 - 5 / 2 = 115

5 / 2 x  - 7.5 = 115

2.5x  = 115 + 7.5

x = 122.5 / 2.5

x = 49

Number of $1 bills = 49

Number of $5 bills = 49 - 5 = 44

Number of $10 bills = 1 / 2 (49 - 5) = 22

learn more on equation here:https://brainly.com/question/13992796

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