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If it takes 35. 04 ml of a 0. 2455 m naoh solution to neutralize 25. 00 ml of an unknown hcl solution, what is the molarity of the hcl solution?

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samueladesida43

If it takes 35.04ml of a 0.2455M NaOH solution to neutralize 25. 00ml of an unknown HCl solution, the molarity of the HCl solution is 0.34M.

How to calculate molarity?

The molarity of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

  • C1 = molarity of acid
  • C2 = molarity of base
  • V1 = volume of acid
  • V2 = volume of base

According to this question, it takes 35. 04ml of a 0. 2455M NaOH solution to neutralize 25.00ml of an unknown HCl solution. The molarity of the HCl can be calculated as follows:

35.04 × 0.2455 = 25.0 × V2

8.602 = 25C2

C2 = 8.6/25

C2 = 0.34M

As a result, the molarity of the HCl solution is 0.34M if it takes 35. 04ml of a 0.2455M NaOH solution to neutralize 25ml of an unknown HCl solution.

Learn more about molarity at: https://brainly.com/question/8732513

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