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The roots of the quadratic equation x 2 − 51x + k = 0 differ by 75, where k is a real number. Determine the sum of the squares of the roots

Sagot :

tushargupta0691

The sum of the squares of the root is 4113

In a quadratic equation ax² + bx + c , the sum of the roots is -b/a and the product of the roots is c/a

Let m, n be roots of the given equation.

So,

m - n = 75                            -1)

m + n = 51  (as sum of roots of a quadratic equation is -b/a)                          -2)

adding both equations 1) and 2)

2m = 75 + 51

2m = 126

m = 63

substituting value of m in equation 1 we get

63 - n = 75

n = -12

So the sum of squares of the roots of the equation is = 63² + -12²

= 3969 + 144

= 4113

Learn more about Quadratic Equation here :

https://brainly.com/question/17177510

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