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Sagot :
Answer:
32 mm²
Step-by-step explanation:
perimeter of left rectangle = 2(9 mm + 3 mm) = 24 mm
length of right rectangle = L
perimeter of right rectangle = 2(L + 4 mm) = 2L + 8
perimeter of right rectangle = 24 mm
The perimeter of the right triangle is 2L + 8 and also 24, so 2L + 8 must equal 24. We can solve for L and find the length of the right rectangle.
2L + 8 = 24
2L = 16
L = 8
area of right triangle = length × width
area = 8 mm × 4 mm
area = 32 mm²
**Disclaimer** Hi there! I assumed the purple triangle to be the one on the right. The following answer will be according to this understanding. If I am wrong, please let me know and I will modify my answer.
Answer: [tex]\Large\boxed{Area=32~mm^2}[/tex]
Step-by-step explanation:
Given information
Rectangle A:
- Base (b) = 3 mm
- Height (h) = 9 mm
Rectangle B:
- Base (b) = 4 mm
- Height (h) = ?
Both rectangles have the same perimeter
Given formula
1) P = 2 (b + h)
- P = Perimeter
- b = base
- h = height
2) A = b × h
- A = Perimeter
- b = base
- h = height
Find the height of rectangle B
Substitute values into 1) formula to find the perimeter of rectangle A
P = 2 (b + h)
P = 2 (3 + 9)
Simplify by addition
P = 2 × 12
Simplify by multiplication
P = 24 mm
Substitute values into 1) formula to find the perimeter of rectangle B
P = 2 (b + h)
24 = 2 (4 + h)
Divide 2 on both sides
24 / 2 = 2 (4 + h) / 2
12 = 4 + h
Subtract 4 on both sides
12 - 4 = 4 + h - 4
h = 8 mm
Find the area of rectangle B (Purple)
Substitute values into 2) formula
A = b × h
A = 4 × 8
Simplify by multiplication
[tex]\Large\boxed{Area=32~mm^2}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
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