(a) The gravitational force received by each 1 kg mass is 8.66 N.
(b) The magnitude of gravitational acceleration is 8.66 m/s².
(c) The orbital speed of the ISS is 7,663.6 m/s.
(d) The time take for the ISS to orbit round the Earth is 5,558.75 seconds which is equal to 1.54 hours.
Gravitational force received by each 1 kg mass
The gravitational force received by each 1 kg mass is calculated as follows;
F = Gm₁m₂/r²
where;
- m₁ is mass of Earth
- m₂ is mass of ISS
- r is the distance between the ISS and center of Earth
F = (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ x 1) / (6780,000)²
F = 8.66 N
Magnitude of gravitational acceleration
mg = GMm/r²
g = GM/r²
where;
g = (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ ) / (6780,000)²
g = 8.66 m/s²
Orbital Speed of the ISS
v = √GM/r
v = √(6.67 x 10⁻¹¹ x 5.97 x 10²⁴ / 6780,000)
v = 7,663.6 m/s
Time of motion of the ISS round the Earth
T = 2πr/v
T = (2π x 6780,000) / (7663.6)
T = 5,558.75 seconds
1 hour = 3600 seconds
= 5,558.75/3600
= 1.54 hours
Thus, the gravitational force received by each 1 kg mass is 8.66 N.
The magnitude of gravitational acceleration is 8.66 m/s².
The orbital speed of the ISS is 7,663.6 m/s.
The time take for the ISS to orbit round the Earth is 5,558.75 s = 1.54 hours.
Learn more about orbital speed here: https://brainly.com/question/22247460
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