The time taken for the tiny saliva to travel is 0.55 second.
The horizontal distance traveled at speed of 4 m/s is 2.2 m.
The horizontal distance traveled at speed of 20 m/s is 11 m.
Time of motion of the tiny saliva
The time taken for the tiny saliva to travel is calculated as follows;
h = vt + ¹/₂gt²
where;
- v is initial vertical velocity = 0
- g is the acceleration due to gravity
h = 0 + ¹/₂gt²
h = ¹/₂gt²
2h = gt²
t² = 2h/g
t = √(2h/g)
Substitute the given parameters and solve for time of motion;
t = √(2 x 1.5 / 10)
t = 0.55 second
Horizontal distance traveled at speed of 4 m/s
X = Vx(t)
X = (4 m/s)(0.55)
X = 2.2 m
Horizontal distance traveled at speed of 20 m/s
X = (20)(0.55)
X = 11 m
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