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For the first 150 miles of a trip, an car drives at v mph. For the next 200 miles, the car drives at (v
+25) mph. The average speed of the whole trip is 35 mph. Find the value of v.
(A) 20
(B) 25
(C) 30
(D) 35


Sagot :

If for the first 150 miles of a trip, an car drives at v mph, for the next 200 miles, the car drives at (v+25) mph and the average speed of the whole trip is 35 mph, then the value of v will be 20mph (A).

Given Information:

Average speed = 35 mph

Total distance = 150 + 200 = 350 miles

For the first 150 miles of a trip, an car drives at v mph speed

⇒ Time, t1 = 150/v hrs

For the next 200 miles, the car drives at (v+25) mph speed

⇒ Time, t1 = 200 / (v+25) hrs

Now, the formula for average speed is given as,

Total distance / Total time

= [tex]\frac{350}{\frac{150}{v}+\frac{200}{(v+25)} }[/tex]

⇒ [tex]\frac{350}{\frac{150}{v}+\frac{200}{(v+25)} }[/tex] = 35 mph

[tex]\frac{350 v (v+25)}{150(v+25) + 200v}[/tex] = 35

[tex]\frac{350v^{2} + 8750v}{150v +3750 + 200v}[/tex] = 35

350v² + 8750v = 35 (350v + 3750)

v² + 25v = 35v + 375

v² - 10v = 375

v² - 10v - 375 = 0

Now, the above equation for speed can be written as,

v² - 20v + 15v - 375 = 0

v(v-20) + 15(v-20) = 0

(v-20) (v+15) = 0

v = 20

or v = -15

Since, speed is a scalar quantity, it can't be negative. Thus, v = 20 mph

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