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In a population where 81 % of voters prefer Candidate A,
an organization conducts a poll of 15 voters. Find the
probability that 11 of the 15 voters will prefer Candidate


Sagot :

The probability of 11 voters out of 15 voting candidate A is 0.9770

According to the statement

we have given that the percentage of voters is 81% and poll conducts are 15 and we have to find the probability that 11 of the 15 voters will prefer Candidate

So, For this purpose,  

the question in based on binomial probability which means the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes p and q and p+q=1

let probability of choosing candidate A be p

and probability of choosing candidate B be q

In question p=0.81 and q=0.16

n be total number of voters=15

x be number of successes

then P(x=x)= [tex]\frac{n}{x} p^{x} q^{n-x}[/tex]

P(x=11)= [tex]\frac{11}{15} 0.81^{11} 0.16^{4}[/tex]

= 0.9770

So, the probability of 11 voters out of 15 voting candidate A is 0.9770

Learn more about binomial probability here

https://brainly.com/question/15246027

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