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Sagot :
Answer: [tex]\Large\boxed{C.~21}[/tex]
Step-by-step explanation:
The goal of the question
Find the value of 2abcosC
Given information
a = 4
b = 3
c = 2
Given formula (Law of Cosine)
[tex]c^2=a^2+b^2-2abcosC[/tex]
Substitute values into the formula (Leave 2abcosC as it is)
[tex](2)^2=(4)^2+(3)^2-2abcosC[/tex]
Simplify the exponents
[tex]4=16+9-2abcosC[/tex]
Simplify by addition
[tex]4=25-2abcosC[/tex]
Add 2abcosC on both sides
[tex]4+2abcosC=25-2abcosC+2abcosC[/tex]
[tex]4+2abcosC=25[/tex]
Subtract 4 on both sides
[tex]4 + 2abcosC-4=25-4[/tex]
[tex]\Large\boxed{2abcosC=21}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
Answer:
C
Step-by-step explanation:
a² + b² - 2abcosC = c² ( subtract a² + b² from both sides )
- 2abcosC = c² - a² - b² ( multiply through by - 1 )
2abcosC = a² + b² - c²
a, b, c are the sides opposite vertices A, B, C
here a = 4 , b = 3 , c = 2 , then
a² + b² - c²
= 4² + 3² - 2²
= 16 + 9 - 4
= 25 - 4
= 21
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