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A weight lifter lifts a mass of 250 kg with a force of 5000N to a height of 5m. a. What is the workdone by the weight lifter? b. What is the workdone by the gravity? c. What is the net workdone on the object?
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Sagot :

Answers are:

a. The work done by the weight lifter W = 25000 Joule

b. The work done by the gravity W = 12250 Joule

c. The net work done on the object W = 12750 Joule

What is Work ?

Work is the product of force and distance in the direction of the force applied. That is, W = F x h

The S.I unit is Joule.

Given that a weight lifter lifts a mass of 250 kg with a force of 5000N to a height of 5m.

The given parameters are;

  • Mass  m = 250 kg
  • Force F = 5000 N
  • Height h = 5 m

a. The work done by the weight lifter will be

W = F x h

W = 5000 x 5

W = 25000 Joule

b. The work done by the gravity will be

W = mg x h

W = 250 x 9.8 x 5

W = 12250 Joule

c. The net work done on the object will be

W = 25000 - 12250

W = 12750 Joule

Since the work done by the gravity is in opposite direction to the work done by the weight lifter, the net work done on the object will be the difference between the two.

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