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Sagot :
The y factors of the given quadratic equation is -1 and 40/22.
According to the statement
we have given that the equation and we have to find the factors of those equation.
So, The given equation is:
[tex]Y =x^2-23x^2 + 18x+40[/tex]
where y is the factors of that equation.
So, we have to find the factors of the given quadratic equation.
[tex]x^2-23x^2 + 18x+40 = 0[/tex]
Then after solving it become
[tex]-22x^2 + 18x+40 = 0[/tex]
Then take negative sign common from it then
[tex]22x^2 - 18x - 40 = 0[/tex]
Make the factors of this quadratic equation
[tex]22x^2 + 22x -40x - 40 = 0[/tex]
Now take common values 22x and 40 from the equation then
[tex]22x (x + 1) -40 (x + 1) = 0[/tex]
Then it become
[tex](22x - 40) (x + 1) = 0[/tex]
Then the values of x become from the equation is
[tex]x = -1, x= 40/22[/tex]
The value of the factors y is -1 and 40/22.
So, The y factors of the given quadratic equation is -1 and 40/22.
Learn more about Quadratic equation here
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