The change in potential energy of the proton is 5.6 x [tex]10^{-17}[/tex] Joule
A uniform electric field is where the electric field strength is the same at all points in the field. In the uniform field, the force experienced by a charge is the same no matter where it is placed in the field.
Given that a proton moves a distance 10 cm in a uniform electric field of 3.5 kN C, in the direction of the field.
The Work done = Fd
but F = Eq
Recall that Electric field E = F/q = V/d
Where V = potential difference.
Let us first calculate the V
E = V/d
V = Ed
Substitute all the parameters into the formula above
V = 3.5 × 10³ × 0.1
V = 350 v
from F/q = V/d
make F the subject of formula and substitute it in work formula
F = Vq/d
W.D = Vq/d x d
W.D = Vq
Substitute all the parameters into the formula above
W.D = 350 x 1.6 x [tex]10^{-19}[/tex]
W.D = 5.6 x [tex]10^{-17}[/tex] J
Work done = Energy = Potential Energy
Therefore, the change in potential energy of the proton is 5.6 x [tex]10^{-17}[/tex] Joule
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