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Calcium Oxide at mass 14.0g react with water. Determine the mass at which the calcium hydroxide formed. [ Ca=40, O=16, H=1]​

Sagot :

Calcium oxide CaO = 40+16 = 56
Calcium hydroxide Ca(OH)_2 = 40+16+16+1+1 = 74

The ratio 56:74 is equal to 14:x with x being the unknown mass.
56/14 = 4
74/4 = 18.5
So the answer is 18.5g assuming the water is in excess
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