eaintmyintmyat2005
Answered

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The sum of two numbers is 56. The first number is 2 times greater than the second number. What is the second number?​

Sagot :

wegnerkolmp2741o

Answer:

y = 56/3

Step-by-step explanation:

We need to write equations to solve

Let the two numbers be x and y

The sum is 56

x+y = 56

The first number is 2 times greater than the second number.

x = 2*y

Substitute this into the first equation

x+y = 56

2y+y=56

3y = 56

y = 56/3

michaeladade999

Step-by-step explanation:

Let the numbers be x and y

The sum of the two numbers is 56 :

Step 1:

X + Y = 56.......... (1)

Also, the first number is 2 times greater than the second number:

Step 2:

2X + Y = 0........... (2)

By substitution method, make Y the subject from (2)

Step 3:

Y = -2X .......... (3)

Put (3) into (1)

Step 4

X - 2X = 56

-X = 56

[tex] \frac{ - x}{ - 1} = \frac{56}{ - 1} [/tex]

X = -56

Put X=56 into (3)

Step 5

[tex]y = - 2( - 56)[/tex]

[tex]y = 112[/tex]

The second number is now 112.

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