Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

What mass (g) of solute is contained in 417 mL of a 0.327 M magnesium fluoride (MgF2) solution?

Sagot :

eunice1234

Answer: [tex]\Large\boxed{m=8.5~g}[/tex]

Rounded to the nearest 2 significant figures

Explanation:

Given information

Volume of Solution = 417 mL

Molarity of Solution = 0.327 M (mol / L)

Given molecular weight

Mg (Magnesium) = 24 g / mol

F (Flourine) = 19 g / mol

Total Weight (MgF₂) = 24 + 2 × 19 = 62 g /mol

Given formula

m = V × M × n

  • m = mass
  • V = Volume
  • M = Molarity
  • n = molar mass (molecular weight)

Convert the unit of volume to Liter

1 L = 1000 mL

417 mL = 417 / 1000 = 0.417 L

Substitute values into the given formula

m = (0.417) × (0.327) × (62)

Simplify by multiplication

m = 136.359 × 62

[tex]\Large\boxed{m=8.5~g}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.