Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

What mass (g) of solute is contained in 417 mL of a 0.327 M magnesium fluoride (MgF2) solution?

Sagot :

eunice1234

Answer: [tex]\Large\boxed{m=8.5~g}[/tex]

Rounded to the nearest 2 significant figures

Explanation:

Given information

Volume of Solution = 417 mL

Molarity of Solution = 0.327 M (mol / L)

Given molecular weight

Mg (Magnesium) = 24 g / mol

F (Flourine) = 19 g / mol

Total Weight (MgF₂) = 24 + 2 × 19 = 62 g /mol

Given formula

m = V × M × n

  • m = mass
  • V = Volume
  • M = Molarity
  • n = molar mass (molecular weight)

Convert the unit of volume to Liter

1 L = 1000 mL

417 mL = 417 / 1000 = 0.417 L

Substitute values into the given formula

m = (0.417) × (0.327) × (62)

Simplify by multiplication

m = 136.359 × 62

[tex]\Large\boxed{m=8.5~g}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.