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What mass (g) of solute is contained in 417 mL of a 0.327 M magnesium fluoride (MgF2) solution?

Sagot :

eunice1234

Answer: [tex]\Large\boxed{m=8.5~g}[/tex]

Rounded to the nearest 2 significant figures

Explanation:

Given information

Volume of Solution = 417 mL

Molarity of Solution = 0.327 M (mol / L)

Given molecular weight

Mg (Magnesium) = 24 g / mol

F (Flourine) = 19 g / mol

Total Weight (MgF₂) = 24 + 2 × 19 = 62 g /mol

Given formula

m = V × M × n

  • m = mass
  • V = Volume
  • M = Molarity
  • n = molar mass (molecular weight)

Convert the unit of volume to Liter

1 L = 1000 mL

417 mL = 417 / 1000 = 0.417 L

Substitute values into the given formula

m = (0.417) × (0.327) × (62)

Simplify by multiplication

m = 136.359 × 62

[tex]\Large\boxed{m=8.5~g}[/tex]

Hope this helps!! :)

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