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complete the following table and calculate the decrease in the freezing point of water when 1 mol glycerol (CH3OH-CHOH-CH2OH), NaCI or Na2CO3 is dissolved in 1.00 kg of water

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The decrease in the freezing point of the solution is −1.86oC.

What is the decrease in the freezing point?

Now we know that the freezing point depression of a solid is a colligative property of the solution.

Thus we have that;

ΔT = K m i

ΔT = freezing point depression

K = freezing constant

m = molality of the solution

i = Van't Hoff factor

Thus;

molality =  1 mol/1 Kg = 1 m

ΔT = −1.86oC/m * 1 m * 1

ΔT =−1.86oC

Learn  more about freezing point:https://brainly.com/question/3121416

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