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Sagot :
A 1. 30-g sample of an unknown gas occupies 798 ml at 25. 0°C and a pressure of 1. 00 atm the the molar mass of the gas is
Calculation ,
According to ideal gas equation ,
PV = nRT ....(i)
where P is the pressure = 1atm
V is the volume of the unknown gas = 798 ml = 0.798 L
R is the universal gas constant = 0.082 atm L /K mol
T is the temperature of the gas = 25 °C = 298 K
n is the number of moles = ?
By putting the value of pressure , volume , temperature and universal gas constant in equation ( i) we get
1 atm ×0.798 L = n×0.082×298
n = 1 atm ×0.798 L/0.082×298 = 0.0326 mole
Number of moles (n) = given mass/ molar mass
molar mass = given mass/number of moles = 1. 30 g/0.0326 mole
molar mass = 39.87 g/mol
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