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Find the volume occupied by 22. 0 g of helium gas at 26. 0 ° C and 1. 20 atm of pressure.

Sagot :

The volume occupied by 22. 0 g of helium gas at 26. 0 ° C and 1. 20 atm of pressure is 112.37 L .

Calculation ,

According to ideal gas equation ,

PV = nRT        ....(i)

where P is the pressure = 1. 20 atm

V is the volume of the helium gas = ?

R is the universal gas constant = 0.082 atm L /K mol

T is the temperature of the gas =  26. 0 ° C = 299 K

n is the number of moles

Number of miles (n)  = given mass/ molar mass =22 g/4 = 5.5 moles

By putting the value of pressure , volume , temperature and  universal gas constant  in equation ( i) we get

1. 20 atm ×V = 5.5 moles × 0.082×299

V = 5.5 moles × 0.082×299/1. 20 atm = 112.37 L

To learn more about helium gas please click here ,

https://brainly.com/question/13645498

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