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Sagot :
The value of [tex](102)^3[/tex] exists 1061208.
How to estimate the value of [tex](102)^3[/tex]?
Let us rewrite [tex](102)^3[/tex] as [tex](100+2)^3[/tex]
Now utilizing the identity [tex](a+b)^3=a^3+b^3+3ab(a+b)[/tex], we get
a = 100 and b = 2 then substitute the values of a and b then
[tex](100+2)^3=100^3+2^3+[(3\times100\times2)(100+2)][/tex]
= 1000000 + 8 + (600 × 102)
= 1000000 + 8 + 61200
= 1061208
Hence, [tex](102)^3=1061208[/tex]
Therefore, the value of [tex](102)^3[/tex] exists 1061208.
To learn more about cubic polynomial equation refer to:
https://brainly.com/question/28181089
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