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Sagot :
Answer:
○ [tex]x = -7[/tex]
Step-by-step explanation:
Given the equation:
[tex]10(x + 10) - 4 = 11 - 5(2x + 11)[/tex],
to solve for [tex]x[/tex], we have to rearrange the equation to make [tex]x[/tex] its subject.
[tex]10(x + 10) - 4 = 11 - 5(2x + 11)[/tex]
⇒ [tex]10x + 100 - 4 = 11 - 10x -55[/tex] [expand brackets]
⇒ [tex]10x + 96 = -44 - 10x[/tex]
⇒ [tex]10x + 10x + 96 = -44[/tex] [add [tex]10x[/tex] to both sides]
⇒ [tex]20x + 96 = -44[/tex]
⇒ [tex]20x = -44 - 96[/tex] [subtract 96 from both sides]
⇒ [tex]20x = -140[/tex]
⇒ [tex]x = \frac{-140}{20}[/tex] [divide both sides by 20]
⇒ [tex]x = \bf-7[/tex]
Answer:
B) x = -7
Step-by-step explanation:
Given equation: [tex]10(x+10)-4=11-5(2x+11)[/tex]
Step 1: Distribute [tex]10[/tex] and [tex]-5[/tex] through the parentheses.
[tex]\implies 10(x)+10(10)-4=11-5(2x)-5(11)[/tex]
[tex]\implies 10x+100-4=11-10x-55[/tex]
Step 2: Simplify (combine like terms).
[tex]\implies 10x+100-4=11-10x-55[/tex]
[tex]\implies 10x+96=-44-10x[/tex]
Step 3: Add [tex]10x[/tex] to both sides.
[tex]\implies 10x+10x+96=-44-10x+10x[/tex]
[tex]\implies 20x+96=-44[/tex]
Step 4: Subtract [tex]96[/tex] from both sides.
[tex]\implies 20x+96-96=-44-96[/tex]
[tex]\implies 20x=-140[/tex]
Step 5: Divide both sides by [tex]20[/tex] to isolate [tex]x[/tex].
[tex]\implies \dfrac{20x}{20}=\dfrac{-140}{20}[/tex]
[tex]\implies \boxed{x=-7}[/tex]
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