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A proton travels with a speed of 8. 34×10^5 m/s at an angle of 32. 3° with the direction of a magnetic field. the field exerts a force of 3. 00×10^−17 n on the proton. What is the strength of the field?

Sagot :

temdan2001

Magnetic field strength of the field is  4.2 × [tex]10^{-4}[/tex] T

What is Magnetic Field ?

The region of space where magnetic force is experienced is known as magnetic field.

The force on a particle of charge q moving at speed v at an angle Ф to a uniform magnetic field of flux density B is given as

F = BqvsinФ

Given that a proton travels with a speed of 8. 34×10^5 m/s at an angle of 32. 3° with the direction of a magnetic field. the field exerts a force of 3. 00×10^−17 N on the proton. What is the strength of the field?

The parameters are;

  • Force F = 3.0 × 10^−17 N
  • Speed V = 8.34 × 10^5 m/s
  • Angle Ф =  32. 3°
  • Magnetic field strength B = ?
  • Proton charge = 1.6 x [tex]10^{-19}[/tex] C

Substitute all the parameters into the formula

F = BqvsinФ

3.0 × [tex]10^{-17}[/tex] = ( 1.6 x [tex]10^{-19}[/tex]  x 8.34 x [tex]10^{5}[/tex] x sin 32.3 ) B

3.0 × [tex]10^{-17}[/tex]  = 7.13 × [tex]10^{-14}[/tex] B

Make B the subject of formula

B = 3.0 × [tex]10^{-17}[/tex] / 7.13 × [tex]10^{-14}[/tex]

B = 4.2 × [tex]10^{-4}[/tex] T

Therefore, Magnetic field strength of the field is  4.2 × [tex]10^{-4}[/tex] T

Learn more about Magnetic field strength here: https://brainly.com/question/27750890

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