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A softball pitcher has a 0. 431 probability of throwing a strike for each pitch. if the softball pitcher throws 22 pitches, what is the probability that exactly 12 of them are strikes?

Sagot :

The probability that exactly 12 of them are strikes is 0.09.

In this question,

Number of pitches, n = 22

Probability of throwing a strike for each pitch, p = 0.431

Then, q = 1 - p

⇒ q = 1 - 0.431

⇒ q = 0.569

Number of strikes, x = 12

The probability that exactly 12 of them are strikes can be calculated using Binomial expansion,

[tex]P(X=x)=nC_xP^{x}q^{(n-x)}[/tex]

⇒ [tex]P(X=12)=22C_{12}(0.431)^{12}(0.569)^{(22-12)}[/tex]

⇒ [tex]P(X=12)=22C_{12}(0.431)^{12}(0.569)^{10}[/tex]

⇒ [tex]P(X=12)=(\frac{22!}{12!10!} )(0.431)^{12}(0.569)^{10}[/tex]

⇒ P(X=12) = (646646)(0.000041)(0.00355)

⇒ P(X=12) = 0.09431 ≈ 0.09

Hence we can conclude that the probability that exactly 12 of them are strikes is 0.09.

Learn more about probability here

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