annieyolol
Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

BRIANLY FOR THE BEST EXPLANATION AND ANSWER!
Question: A circle has an area of 16mm². Find it's circumference.

Sagot :

xKavinsky

Answer:

C ≈ 14.18

Step-by-step explanation:

Question Given:

A circle has an area of 16mm². Find it's circumference.

Formula:

C = 2√πA

Solve:

C = 2√πA

C = 2√(3.14 × 16)

C = 2√50.24

C = 14.1760361173

C ≈ 14.18

Hence, Circumference is approximately 14.18.

~Kavinsky

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

Area of Circle :

[tex]\qquad \sf  \dashrightarrow \: \pi {r}^{2} [/tex]

Now, it's given that area of circle is : 16 mm²

Let's calculate Radius ~

[tex]\qquad \sf  \dashrightarrow \: \pi {r}^{2} = 16[/tex]

[tex] \qquad \sf  \dashrightarrow \: {r}^{2} = \cfrac{16}{ \pi} [/tex]

[tex]\qquad \sf  \dashrightarrow \: r = \sqrt{ \cfrac{16}{ \pi} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: r = { \cfrac{4}{ \sqrt{ \pi} } }[/tex]

Now,

[tex]\qquad \sf  \dashrightarrow \: circumference = 2\pi r[/tex]

[tex]\qquad \sf  \dashrightarrow \: c = 2 \pi \cfrac{4}{ \sqrt{ \pi} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: c = 8 \sqrt{ \pi} [/tex]

[ for approximate value take pi = 3.14 ]

[tex]\qquad \sf  \dashrightarrow \: c = 8 \sqrt{3.14} [/tex]

[tex]\qquad \sf  \dashrightarrow \: c \approx 8 \times 1.77[/tex]

[tex]\qquad \sf  \dashrightarrow \: c \approx 14.18 \: \: mm[/tex]

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.