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Calculate the energy of the violet light emitted by a hydrogen atom with a wavelength of 410. 1 nm

Sagot :

The energy of the violet light emitted by a hydrogen atom with a wavelength of 410. 1 nm will be 4.85 * [tex]10^{-19}[/tex] J

Light energy is a form of electromagnetic radiation that comprises wavelengths that the common human eye can detect. Light is a type of kinetic energy. It consists of particles like photons, which have wave-like properties. It can affect the physiology of an organism, like photosynthesis or the sense of sight.

Energy = h*c / lambda

where

h = plank's constant  =  6.626 * [tex]10^{-34}[/tex] J-s

c = speed of light  = 3 * [tex]10^{8}[/tex] m/s

lambda = wavelength = 410. 1 nm = 410. 1  * [tex]10^{-9}[/tex] m

Energy = 6.626 * [tex]10^{-34}[/tex] *  3 * [tex]10^{8}[/tex]  / 410. 1  * [tex]10^{-9}[/tex]

            = 4.85 * [tex]10^{-19}[/tex] J

To learn more about wavelength here

https://brainly.com/question/4112024

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