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Sagot :
The wavelength of an electron (m = 9. 11 × 10^-28 g) moving at 3. 66 × 10^6 m/s will be 0.197 * [tex]10^{-12}[/tex] m
De Broglie wavelength is an important concept while studying quantum mechanics. The wavelength (λ) that is associated with an object in relation to its momentum and mass is known as de Broglie wavelength. A particle's de Broglie wavelength is usually inversely proportional to its force.
momentum (p) = mv
DE Broglie wavelength = lambda = h / p
where
h = plank's constant
m = mass of electron
v = velocity of electron
lambda = h / mv
= 6.633 * [tex]10^{-34}[/tex] / 9. 11 × [tex]10^{-28}[/tex] * 3. 66 × [tex]10^{6}[/tex]
= 0.197 * [tex]10^{-12}[/tex] m
To learn more about de Broglie wavelength here
https://brainly.com/question/17295250
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