Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
The wavelength of an electron (m = 9. 11 × 10^-28 g) moving at 3. 66 × 10^6 m/s will be 0.197 * [tex]10^{-12}[/tex] m
De Broglie wavelength is an important concept while studying quantum mechanics. The wavelength (λ) that is associated with an object in relation to its momentum and mass is known as de Broglie wavelength. A particle's de Broglie wavelength is usually inversely proportional to its force.
momentum (p) = mv
DE Broglie wavelength = lambda = h / p
where
h = plank's constant
m = mass of electron
v = velocity of electron
lambda = h / mv
= 6.633 * [tex]10^{-34}[/tex] / 9. 11 × [tex]10^{-28}[/tex] * 3. 66 × [tex]10^{6}[/tex]
= 0.197 * [tex]10^{-12}[/tex] m
To learn more about de Broglie wavelength here
https://brainly.com/question/17295250
#SPJ4
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.
