Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
The wavelength of an electron (m = 9. 11 × 10^-28 g) moving at 3. 66 × 10^6 m/s will be 0.197 * [tex]10^{-12}[/tex] m
De Broglie wavelength is an important concept while studying quantum mechanics. The wavelength (λ) that is associated with an object in relation to its momentum and mass is known as de Broglie wavelength. A particle's de Broglie wavelength is usually inversely proportional to its force.
momentum (p) = mv
DE Broglie wavelength = lambda = h / p
where
h = plank's constant
m = mass of electron
v = velocity of electron
lambda = h / mv
= 6.633 * [tex]10^{-34}[/tex] / 9. 11 × [tex]10^{-28}[/tex] * 3. 66 × [tex]10^{6}[/tex]
= 0.197 * [tex]10^{-12}[/tex] m
To learn more about de Broglie wavelength here
https://brainly.com/question/17295250
#SPJ4
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
