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Sagot :
Current in the inductor, I = 100A
Given,
Magnetic potential energy stored, U= 30 joule
Inductance, L = 6.0 H
Therefore, current in the inductor, [tex]I^{2}[/tex]= (2×30×10^3) ÷ 6
= 2×5×10^3
= 10×10^3
[tex]I^{2}[/tex] = 10000
I = √10000
I = 100A
Concept:-
- As a result of the magnetic forces that magnets exert on one another, magnetic potential energy is the energy that is stored in a system of magnets.
- Magnetic potential energy stored in an inductor, U = 1/2 (L[tex]I^{2}[/tex])
- L is the inductance of the inductor.
- I is the current flowing through the inductor.
Learn more about Current here: https://brainly.com/question/17403680
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